如何在c中实现计数hashmap？

我有6个常量字符串（每个5个字母）

我得到了几个单词的流（在这6个单词中）。

我想计算每个单词出现的次数。

我怎样才能在C中实现它？

我试过了：

char searchEngineNames[6][5] = { "waze_", "faceb", "fours", "googl", "fueli", "yello" }; static void foo(const char* res_name, int success, void *context, char *last_modified) { if (success){ for (int i=0; i<6; i++) { char substringFiveChars[6]; strncpy(substringFiveChars, res_name, 5); char substringFiveChars[6]; substringFiveChars[5] = 0; if (strcmp(searchEngineNames[i],substringFiveChars) == 0) { ... } .. } 

例如，对于此流：

“的Wooo _”， “的Wooo _”， “faceb”， “的Wooo _”， “谷歌”

我最终会得到：

 "wooo_" 3 times "faceb" 1 times "google" 1 times "fours" 0 times "fuelil" 0 times "yello" 0 times 

Answer 1

我使用2个数组而不是1个。

 char searchEngineNames[6][5] = { "wooo_", "faceb", "fours", "google", "fuelil", "yello" }; int searchEngineCounts[6] = {0,0,0,0,0,0}; static void foo(const char* res_name, int success, void *context, char *last_modified) { if (success) { int i = 0; for (i; i < 6; i++) { char substringFiveChars[6]; strncpy(substringFiveChars, res_name+7, 5); substringFiveChars[5] = 0; if (strcmp(searchEngineNames[i], substringFiveChars) == 0) { searchEngineCounts[i]++; if (searchEngineCounts[i] < 3) { ... } } } } }