一个程序中的多个scanf导致c崩溃？

#include  int main() { printf("how old are you? "); int age = 0; scanf("%d", age); printf("how much does your daily habit cost per day? \n"); int daily = 0; scanf("%d", daily); double thisyear = daily * 365; printf("\n"); printf("this year your habit will cost you: %.2f", thisyear); return 0; } 

这是我的学校计划，当我写这篇文章的时候，我试图让用户1，给他们的年龄和2，他们的日常生活费用。 但是当我运行它时，我的程序会崩溃

Answer 1

scanf（“％d”，每日）;

需要成为

 scanf("%d", &daily); 

您需要将变量的地址（即指针，使用& ）传递给scanf以便可以更改变量的值。 这同样适用于您的其他提示。 将其更改为

 scanf("%d", &age); 

现在你应该在运行程序时得到这个：

 % a.out how old are you? 30 how much does your daily habit cost per day? 20 this year your habit will cost you: 7300.00 

Answer 2

scanf函数需要一个指针。

 scanf("%d", &age); 

同样在“每日”扫描的行。

Answer 3

scanf适用于对变量的引用

 printf("how old are you? "); int age = 0; scanf("%d", &age); printf("how much does your daily habit cost per day? \n"); int daily = 0; scanf("%d", &daily); double thisyear = daily * 365; printf("\n"); printf("this year your habit will cost you: %.2f", thisyear);