从C中的hex字符串转换为ASCII字符串
我试图将hex字符串转换为其等效的ASCII。 我被赋予字符串的“hex”值作为字符串，即代替“ABCD”我得到“41424344”。 我只需要提取41这将是我的hex值并重新编码为“ABCD”。 这就是我所拥有的。
int main(int argc, char *argv[]){ char *str = "ABCD"; unsigned int val = 0; int i = 0; int MAX = 4; for (i = 0; i<MAX; i++){ val = (str[i] & 0xFF); //printf("dec val= %d\n", val); //printf("hex val= %02x\n", val); } val = 0; char *hexstr = "41424344"; char *substr = (char*)malloc(3); char *ptr = hexstr; for (i = 0; i<8; i++){ strncpy(substr, ptr, 2); printf("substr = %s\n", substr); int s = atoi(substr); printf("s= %d\n", s); ptr= ptr+2; i = i+2; } return 0; } 事情是从这里开始，我必须使这个“s”值成为hex值而不是int。 如何才能做到这一点？
更新：
以下是我的答案后的答案：
#include #include #include int main(int argc, char *argv[]){ char *str = "ABCD"; unsigned int val; val = 0; int i = 0; int MAX = 4; for (i = 0; i<MAX; i++){ val = (str[i] & 0xFF); //printf("dec val= %d\n", val); //printf("hex val= %02x\n", val); } val = 0; char *hexstr = "41424344"; char *substr = (char*)malloc(3); char *ptr = hexstr; char *retstr = (char *)malloc(5); char *retptr = retstr; for (i = 0; i<8; i+1){ strncpy(substr, ptr, 2); printf("substr = %s\n", substr); int s = strtol(substr, NULL, 16); printf("s= %d\n", s); ptr= ptr+2; i = i+2; sprintf(retptr, "%c", s); retptr = retptr +1; } printf("retstr= %s\n", retstr); return 0; }
改变你的“s”变量线
int s = atoi(substr);
至
int s = strtol(substr, NULL, 16);