char *来自文件时有所不同

我的C程序在FILE中存储一个shell命令输出，将它传递给一个char数组并打印它。

您不需要查看程序中的函数，因为问题出在main上。

我的shell中命令的输出是：

$ cmus-remote -Q | grep 'tag title' | sed s/'tag title'/''/g The View From The Afternoon 

gdb中的char值是：

 34 fclose(tmp2); (gdb) print title $4 = 0x603010 " The View From The Afternoon\n" (gdb) n 51 char *lyric = lyrics_get(artist, title); (gdb) print title $5 = 0x603010 " The View From The After\001\002" 

这是代码

 #include  #include  #include  #include "/usr/include/glyr/glyr.h" #include  #include  char *lyrics_get(char *a, char *b); int main(void) { FILE *tmp1; FILE *tmp2; char *artist; char *title; tmp1 = popen("cmus-remote -Q | grep 'tag artist' | sed s/'tag artist'/''/g | sed '1s/^.//'", "r"); tmp2 = popen("cmus-remote -Q | grep 'tag title' | sed s/'tag title'/''/g", "r"); fseek(tmp1, 0, SEEK_END); size_t size1 = ftell(tmp1); rewind(tmp1); artist = malloc((size1 +1) * (sizeof(char))); fread(artist, sizeof(char), size1, tmp1); fclose(tmp1); fseek(tmp2, 0, SEEK_END); size_t size2 = ftell(tmp2); rewind(tmp2); title = malloc((size2 +1) * (sizeof(char))); fread(title, sizeof(char), size2, tmp2) fclose(tmp2); char *lyric = lyrics_get(artist, title); printf("%s", title); printf("%s", artist); printf("%s", lyric); return 0; } char *lyrics_get(char *a, char *b) { glyr_init(); atexit (glyr_cleanup); GlyrQuery q; glyr_query_init (&q); glyr_opt_type (&q,GLYR_GET_LYRICS); glyr_opt_artist (&q, (a)); glyr_opt_title (&q, (b)); glyr_opt_force_utf8 (&q, true); GLYR_ERROR err; GlyrMemCache * head = glyr_get (&q,&err,NULL); return (head->data); glyr_free_list(head); glyr_query_destroy(&q); } 

为什么会有所不同？