数组声明有什么问题：“八进制常量中的无效数字”？
int arr[20][20] = { {08,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,08}, {49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00}, {81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65}, {52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91}, {22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80}, {24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50}, {32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70}, {67,26,20,68,02,62,12,20,95,63,94,39,63,08,40,91,66,49,94,21}, {24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72}, {21,36,23,09,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95}, {78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,09,53,56,92}, {16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57}, {86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58}, {19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40}, {04,52,08,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66}, {88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69}, {04,42,16,73,38,25,39,11,24,94,72,18,08,46,29,32,40,62,76,36}, {20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16}, {20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54}, {01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48} }; 我收到以下错误
q11.c:8:10: error: invalid digit "8" in octal constant q11.c:8:67: error: invalid digit "8" in octal constant q11.c:15:49: error: invalid digit "8" in octal constant q11.c:17:19: error: invalid digit "9" in octal constant q11.c:18:58: error: invalid digit "9" in octal constant q11.c:22:16: error: invalid digit "8" in octal constant q11.c:24:46: error: invalid digit "8" in octal constant
不要在数字前加0 ，除非你希望它们被视为八进制，显然你不会。 所以只需使用8而不是08 。
如果你坚持要保持一切正确对齐，即使是一位数的数字，也只需使用空格而不是零。
问题是你用0开始一些数字，这意味着它们是八进制数（基于8）
带有前导零的数字被编译器视为八进制，因此，大于7的数字会触发错误。
在CPP中，八进制数以0（零）开始，八进制值在0-7范围内，因此08和09始终是编译器的未知八进制常量，最好从08和09中删除零（前缀）。