如何使用C将二进制字符串转换为hex？

如何使用C将8位二进制字符串（例如“10010011”）转换为hex？

Answer 1

像这样的东西：

char *bin="10010011"; char *a = bin; int num = 0; do { int b = *a=='1'?1:0; num = (num<<1)|b; a++; } while (*a); printf("%X\n", num); 

Answer 2

 #include  strtol("10010011", NULL, 2); 

Answer 3

 void binaryToHex(const char *inStr, char *outStr) { // outStr must be at least strlen(inStr)/4 + 1 bytes. static char hex[] = "0123456789ABCDEF"; int len = strlen(inStr) / 4; int i = strlen(inStr) % 4; char current = 0; if(i) { // handle not multiple of 4 while(i--) { current = (current << 1) + (*inStr - '0'); inStr++; } *outStr = hex[current]; ++outStr; } while(len--) { current = 0; for(i = 0; i < 4; ++i) { current = (current << 1) + (*inStr - '0'); inStr++; } *outStr = hex[current]; ++outStr; } *outStr = 0; // null byte } 

Answer 4

怎么样

 char *binary_str = "10010011"; unsigned char hex_num = 0; for (int i = 0, char *p = binary_str; *p != '\0'; ++p, ++i) { if (*p == '1' ) { hex_num |= (1 << i); } } 

现在你已经有了hex_num，你可以用它做你想做的事。 请注意，您可能需要validation输入字符串的长度或将循环限制为hex_num中的位数。