如何在C中的char数组中搜索字符串？

例如我有：

char buff[1000]; 

我想搜索字符串“hassasin”是否在该char数组中。 这是我尝试过的。

 char word[8] = "hassasin"; char Buffer[1000]=sdfhksfhkasd/./.fjka(hassasin)hdkjfakjsdfhkksjdfhkjh....etc int k=0; int t=0; int len=0; int sor=0; for (k=0; k<1000; k++){ for (t=0; t<8; t++){ if (Buffer[k]==word[t]) len++; if (len==8) "it founds 0.9.1" } } 

Answer 1

如果chararray包含stringend或者不以\ 0结尾，你可以使用这些代码，因为strstr会对这些代码进行制动：

 #include  int main() { char c_to_search[5] = "asdf"; char text[68] = "hello my name is \0 there is some other string behind it \n\0 asdf"; int pos_search = 0; int pos_text = 0; int len_search = 4; int len_text = 67; for (pos_text = 0; pos_text < len_text - len_search;++pos_text) { if(text[pos_text] == c_to_search[pos_search]) { ++pos_search; if(pos_search == len_search) { // match printf("match from %d to %d\n",pos_text-len_search,pos_text); return; } } else { pos_text -=pos_search; pos_search = 0; } } // no match printf("no match\n"); return 0; } 

http://ideone.com/2In3mr

Answer 2

是的，您可以使用strstr ：

  #include  #include  char buff[1000]; char *s; s = strstr(buff, "hassasin"); // search for string "hassasin" in buff if (s != NULL) // if successful then s now points at "hassasin" { printf("Found string at index = %d\n", s - buff); } // index of "hassasin" in buff can be found by pointer subtraction else { printf("String not found\n"); // `strstr` returns NULL if search string not found }