如何使十进制的值仅以数字显示？
我试图使我的c程序运行任何你输入的值将作为文字出来，例如，如果我想输入值1234.56它应该出来“一千二百三十四美元……和56美分”注意分数只是用数字表示的。 到目前为止，我已经正确编写了能够将数字转换为单词的代码，但我不知道如何只留下单独的分数。 请帮忙！！
目前对于小数，我得到了一些负面的数字！
代码如下：
#include void printNum(int); void printNum2(int); void printNum3(int); void printNum4(int); int main() { int a = 0; int b = 0; int c = 0; int d = 0, e=0; float inclusive; printf("Welcome to the IPC144 Cheque Generator!!\n"); printf("PAY TO THE ORDER OF... amahmood29 (018359133)\n"); printf("Enter a monetary value from $0.01 to $9999.99 inclusive: "); scanf("%f", &inclusive); if(inclusive 9999.99) { printf("Sorry, cannot create cheque for that amount, try again next time!\n"); } else { a = inclusive / 1000; //This data is replacing our variable by diving whatever the value is by either 1000, 100, 10. inclusive = inclusive - (a*1000); b = inclusive / 100; inclusive = inclusive - (b*100); if ( inclusive > 19 ) { c = inclusive / 10; inclusive = inclusive - (c*10); } else { c = inclusive; d = 0; } d = inclusive; e = inclusive; //the variable "e" is for the decimal// inclusive = inclusive - a - b - c printNum(a); //Printing is the variables are in the thousands, hundreds, tens or ones categories.// printf("Thousand "); printNum(b); printf("Hundred "); printNum2(c); printf(""); printNum3(d); printf("Dollars and ... "); printNum4(e); printf("Cents\n"); } } void printNum(int x) { if ( x == 1) printf("One "); else if ( x == 2) printf("Two "); else if (x == 3) printf("Three "); else if (x == 4) printf("Four "); else if (x == 5) printf("Five "); else if (x == 6) printf("Six "); else if (x == 7) printf("Seven "); else if (x == 8) printf("Eight "); else if (x == 9) printf("Nine "); } void printNum2(int x) { if ( x == 10) printf("Ten "); else if ( x == 11) printf("Eleven "); else if ( x == 12) printf("Twelve "); else if ( x == 13) printf("Thirteen "); else if (x == 14) printf("Fourteen "); else if (x == 15) printf("Fifteen "); else if (x == 16) printf("Sixteen "); else if (x == 17) printf("Seventeen "); else if (x == 18) printf("Eighteen "); else if (x == 19) printf("Ninteen "); else if (x == 2) printf("Twenty "); else if (x == 3) printf("Thirty "); else if (x == 4) printf("Forty "); else if (x == 5) printf("Fifty "); else if (x == 6) printf("Sixty "); else if (x == 7) printf("Seventy "); else if (x == 8) printf("Eighty "); else if (x == 9) printf("Ninety "); } void printNum3(int x) { if ( x == 1) printf("One "); else if ( x == 2) printf("Two "); else if (x == 3) printf("Three "); else if (x == 4) printf("Four "); else if (x == 5) printf("Five "); else if (x == 6) printf("Six "); else if (x == 7) printf("Seven "); else if (x == 8) printf("Eight "); else if (x == 9) printf("Nine "); } void printNum4(int x) { printf("%d, e"); } 为了避免int和float之间的混淆，并避免两种类型之间的算术运算问题，我建议
-
scan()输入为float/double。 - 使用
sprintf()将其转换为字符串。 - 使用基于分隔符的
strtok()对字符串进行strtok().（小数点）。 - 第一部分（令牌）是不可或缺的部分，使用转换器function进行转换。
- 第二部分（标记）是表示“美分”的部分。 您可以直接打印。
你可以使用FLOOR函数（舍入到最接近的整数值小于实际值），单独打印并从原始数字中减去 – >然后你将得到美分值，你可以乘以100得到它们的整数值。
您正在隐式地将浮点数转换为int。 分配e =包含时。 这就是为什么你得到奇怪的数字，不要将整数转换为浮点数，反之亦然，永远不要！
实际上你可以使用modulo得到小数部分。
也许你可以试试这个：
void printNum4(float inclusive) { //Decimal part * 100 to get cents float decimal = fmod(inclusive, 1) * 100; //Print a float with a 0 decimal precision printf("%.0f", decimal); }