用于Ubuntu 14.04的C中的UINPUT设备程序不起作用。 为什么？ 第2部分：

我正在使用Ubuntu 14.04，我在c中设置了一个虚拟键盘，这需要输入才能工作。

我的程序应该将密钥’a’发送到终端，就像我按下键盘上的’a’键一样。

这是我的源代码：

int main() { int uinp_fd; int i; /********** Open uinput file section. **********************/ uinp_fd = open("/dev/uinput", O_WRONLY|O_NDELAY); if(uinp_fd < 0) { printf("Unable to open /dev/uinput\n"); return -1; } else printf("Can open /dev/uinput\n"); /********* Setup input device structure section: ***********/ memset(&uinp,0,sizeof(uinp)); snprintf(uinp.name, UINPUT_MAX_NAME_SIZE, "The C Keyboard"); uinp.id.bustype = BUS_USB; uinp.id.version = 1; uinp.id.vendor = 0x1234; uinp.id.product = 0xfedc; write(uinp_fd, &uinp, sizeof(uinp)); /****** Setup the uinput keyboard device section: **********/ ioctl(uinp_fd, UI_SET_EVBIT, EV_KEY); ioctl(uinp_fd, UI_SET_EVBIT, EV_SYN); ioctl(uinp_fd, UI_SET_EVBIT, EV_REP); ioctl(uinp_fd, UI_SET_KEYBIT, KEY_A); if (ioctl(uinp_fd, UI_DEV_CREATE, NULL) < 0) { printf("Unable to create UINPUT device.\n"); return -1; } /*********** Send keypress events to kernel: ***************/ memset(&event, 0, sizeof(event)); gettimeofday(&event.time, NULL); event.type = EV_KEY; event.code = KEY_A; event.value = 1; write(uinp_fd, &event, sizeof(event)); event.type = EV_SYN; event.code = SYN_REPORT; event.value = 0; write(uinp_fd, &event, sizeof(event)); /************** Release keypress event: *******************/ memset(&event, 0, sizeof(event)); gettimeofday(&event.time, NULL); event.type = EV_KEY; event.code = KEY_A; event.value = 0; write(uinp_fd, &event, sizeof(event)); event.type = EV_SYN; event.code = SYN_REPORT; event.value = 0; write(uinp_fd, &event, sizeof(event)); /*** Destroy keyboard device and close the Uinput device: **/ ioctl(uinp_fd, UI_DEV_DESTROY); close(uinp_fd); return 0; } 

然而，我的程序没有做任何事情。 它只打印出来：

 Can open /dev/uinput 

这就是它……

我究竟做错了什么？ 感谢您的帮助！